Qualification > Math
Pure 3 help.
mousa:
--- Quote from: Deadly_king on October 02, 2010, 06:05:09 am ---Well the CIE textbook can be quite helpful. But alone it is quite difficult to understand all that. A teacher would have been really helpful!
Anyway i'll be modifying my posts now and the until I answer all the questions.
However if you do not understand something.......do ask me and i'll try to elaborate more....ok??
--- End quote ---
thanks alot, I will make sure to do that :P
mousa:
--- Quote from: Requiem on October 02, 2010, 01:24:43 am ---Part ii)
2x-y-3z=7----(i)
x+2y+2z=0----(ii)
elminating two variables one by one from the equation of planes,
eq.(i)
eq (ii) * 2
we get z= -5y-7
------- ---------- (iii)
7
eq (i) *2
eq (ii)
we get z=5x-14
-------- --------(iv)
4
from equations (iii) and (iv), we have
z=-5y-7 5x-14
-----= ------
7 4
z-0 -5(y+7/5) 5(x-14/5)
----=-----------= --------
1 7 4
z-0 y+7/5 x-14/5
----=------=---------
1 -7/5 4/5
Therefore the line of intersection of the two planes is
r=(14/5 i +7/5 i +0k)+ dont know how to draw the sign (4/5 i-7/5 j +k)
1
--- End quote ---
I didnt understand this part,can you help me with it?? That is ,How to solve these sort of questions in general??
Deadly_king:
--- Quote from: mousa on October 02, 2010, 06:19:11 am ---I didnt understand this part,can you help me with it?? That is ,How to solve these sort of questions in general??
--- End quote ---
Ok......i'll be finishing Jun 09 and i'll try to explain that :)
elemis:
@deadly_king + rep for all the support you've been giving ;)
Deadly_king:
--- Quote from: Ari Ben Canaan on October 02, 2010, 06:49:14 am ---@deadly_king + rep for all the support you've been giving ;)
--- End quote ---
That's alright br0 :)
We all form part of the huge SF family. So we gotta support each other ;)
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