Qualification > Math
Math P2 MJ 2010 doubts
Arthur Bon Zavi:
For The 15th one:
(a). See the pattern (sequence):
Y co-ordinates are 5, 3 and 1. Means -2 every time, i.e 5-2=3, then 3-2=1.
X co-ordinates are 2, 3 and k. This also has the sequence, i.e 2+1=3, then 3+1=4, so k(x co-ordinate)=4.
(b).
For the Gradient remember the formula:
y2-y1
-------
x2-x1
The Points are, (2,5), (3,3) and (4,1).
take any two points, e.g (2,5) and (3,3).
then:
3 - 5 -2
------ = ----- = -2
3 - 2 1
Gradient (Slope)= -2.
m = gradient = slope = -2.
so:
y=mx+c.
put any of the values.
3=-2*3+c
so,
c=9.
so equation goes:
y=-2*x+9
Or a simpler method if u have gradient, then:
y-y1=m(x-x1), where m is gradient (slope).
Example from this:
y-3=-2(x-3)
y-3=-2x+6
therefore: y=-2x+9. [It's Easy].
Another Method is when u don't have a gradient and have atleast two co-ordinates, so here u have 3 (more than necessary). :D
take any two:
like (2,5), and (3,3).
Equation is :
y-y1 x-x1
----- = ------
y2-y1 x2-x1
so, by substituting:
y -5 x - 2
----- = ------
3 -5 3 - 2
It gives:
y -5 = -2 (x - 2)
y - 5 = -2x+4
y = -2x + 9
Arthur Bon Zavi:
This answer I just explained briefly with the help of alternative known methods, and other answers are explained by Ari.
;)
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