Qualification > Math
COMPLEX NUMBERS
astarmathsandphysics:
Can you also scan in the question? I want to be sure I understood it.
Deadly_king:
--- Quote from: astarmathsandphysics on September 27, 2010, 09:50:19 am ---Can you also scan in the question? I want to be sure I understood it.
--- End quote ---
Sorry.......i don't have a scanner :(
But he has written the question likewise. We just need to find arg((z-1)/(z-i)) in the three cases.
In other words : arg(z-1) - arg(z-i)
astarmathsandphysics:
I thought it was z-1/z-1 but the answer is similar
Deadly_king:
--- Quote from: astarmathsandphysics on September 27, 2010, 10:35:17 am ---I thought it was z-1/z-1 but the answer is similar
--- End quote ---
I just modified my post.
I don't think it's the same.
astarmathsandphysics:
I see. Much easier question. Will do it when I get home.
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