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Maths Paper 1

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houmeira:
can anyone help me with this question please?

Find the equation of the curve which passes through the point (1,6)
and for which dy/dx=(1/sqrt x)(x-2/2x)

i can't integrate it:(

Deadly_king:

--- Quote from: houmeira on September 23, 2010, 05:21:59 pm ---can anyone help me with this question please?

Find the equation of the curve which passes through the point (1,6)
and for which dy/dx=(1/sqrt x)(x-2/2x)

i can't integrate it:(

--- End quote ---

Well am not sure.......it would be nice if someone could confirm the answer.

I got....... y = x1/2 + 2/x1/2 + 3

First you need to multiply the denominators so as to obtain one fraction only. You'll get (x - 2)/(2 x3/2)
Then you separate the fraction again to get 1/(2 x1/2) - 1/(x 3/2)
From there its easier to integrate..........try it out.

If you still cannot do it........let me know. :)

S.M.A.T:
Your answer is correct :)

*Hope*:
+rep DK :D

Deadly_king:
Thanks for confirming my answer asif :)

Thank You *Hope* :)
I told you.........you are very encouraging :)

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