Maths Paper 1

[houmeira]

can anyone help me with this question please?

Find the equation of the curve which passes through the point (1,6)
and for which dy/dx=(1/sqrt x)(x-2/2x)

i can't integrate it:(

[Deadly_king]

can anyone help me with this question please?

Find the equation of the curve which passes through the point (1,6)
and for which dy/dx=(1/sqrt x)(x-2/2x)

i can't integrate it:(

Well am not sure.......it would be nice if someone could confirm the answer.

I got....... y = x^1/2 + 2/x^1/2 + 3

First you need to multiply the denominators so as to obtain one fraction only. You'll get (x - 2)/(2 x^3/2)
Then you separate the fraction again to get 1/(2 x^1/2) - 1/(x ^3/2)
From there its easier to integrate..........try it out.

If you still cannot do it........let me know.

[S.M.A.T]

Your answer is correct

[*Hope*]

+rep DK

[Deadly_king]

Thanks for confirming my answer asif

Thank You *Hope*
I told you.........you are very encouraging

[*Hope*]

Thanks for confirming my answer asif

Thank You *Hope*
I told you.........you are very encouraging

Don't mention it

You really deserve it