« previous next »
Pages: [1]   Go Down

Author Topic: CIE AS P1 Math Problem M/J 2010  (Read 1376 times)

Offline missbeautiful789

  • SF Immigrant
  • **
  • Posts: 55
  • Reputation: 1008
  • Gender: Male
  • Tala al Badru
CIE AS P1 Math Problem M/J 2010
« on: October 11, 2010, 04:40:08 pm »
Please help me with this math problem, im doing AS, so don't use some funky A2 compound angle equations and shtuff.

see question attached, there just 1 mark each. so 3 quick questions

Thank you  in advance
Logged
Allâhumma innî a‘ûdhu bika min al-hammi wa al-hazan. Wa a‘ûdhu bika min al-‘ajzi wa al-kasal.

Wa a‘ûdhu bika min al-jubni wa al-bukhl. Wa a‘ûdhu bika min ghalabat id-dayni wa qahr ir-rijal.

{Oh Allah, I seek refuge in You from worry and grief, from helplessness and laziness, from cowardice an

nid404

  • Guest
Re: CIE AS P1 Math Problem M/J 2010
« Reply #1 on: October 11, 2010, 05:24:15 pm »
Quote from: missbeautiful789 on October 11, 2010, 04:40:08 pm
Please help me with this math problem, im doing AS, so don't use some funky A2 compound angle equations and shtuff.

see question attached, there just 1 mark each. so 3 quick questions

Thank you  in advance

You need to know the functions

tan((\pi-\theta)=-k

tan\ (1/2pi-\theta)= 1/k

sin x= cosx X k

Logged

Offline S.M.A.T

  • SF Master
  • ******
  • Posts: 1595
  • Reputation: 18522
  • Gender: Male
Re: CIE AS P1 Math Problem M/J 2010
« Reply #2 on: October 11, 2010, 05:45:42 pm »
U must now this common relation:
sin(180-x)=sinx ,
cos(180-x)=-cosx,
sin(90-x)=cosx
cos(90-x)=sinx

Logged


"A man's life is interesting primarily when he has failed - I well know. For it's a sign that he tried to surpass himself." Clemenceau, Georges

Offline Deadly_king

  • <<Th3 BO$$>>
  • Global Moderator
  • SF Farseer
  • *****
  • Posts: 3391
  • Reputation: 65078
  • Gender: Male
  • Hard work ALWAYS pays off.........just be patient!
    • @pump_upp - best crypto pumps on telegram !
Re: CIE AS P1 Math Problem M/J 2010
« Reply #3 on: October 11, 2010, 05:58:44 pm »
Quote from: asiftasfiq93 on October 11, 2010, 05:45:42 pm
U must now this common relation:
sin(180-x)=sinx ,
cos(180-x)=-cosx,
sin(90-x)=cosx
cos(90-x)=sinx



+ rep Asif

This question........especially the third one was haunting my mind as well ;)
Logged

nid404

  • Guest
Re: CIE AS P1 Math Problem M/J 2010
« Reply #4 on: October 11, 2010, 06:00:47 pm »
oh only in terms of k :/ My bad.

+ rep asif  :)
Logged

Offline missbeautiful789

  • SF Immigrant
  • **
  • Posts: 55
  • Reputation: 1008
  • Gender: Male
  • Tala al Badru
Re: CIE AS P1 Math Problem M/J 2010
« Reply #5 on: October 11, 2010, 07:40:09 pm »
Oh shucks...i could have used that quadrant angle thingy majig.
trig bones.

Thanks guys, -  thank you Asif 
Logged
Allâhumma innî a‘ûdhu bika min al-hammi wa al-hazan. Wa a‘ûdhu bika min al-‘ajzi wa al-kasal.

Wa a‘ûdhu bika min al-jubni wa al-bukhl. Wa a‘ûdhu bika min ghalabat id-dayni wa qahr ir-rijal.

{Oh Allah, I seek refuge in You from worry and grief, from helplessness and laziness, from cowardice an

Offline S.M.A.T

  • SF Master
  • ******
  • Posts: 1595
  • Reputation: 18522
  • Gender: Male
Re: CIE AS P1 Math Problem M/J 2010
« Reply #6 on: October 11, 2010, 09:58:52 pm »
Quote from: Deadly_king on October 11, 2010, 05:58:44 pm
+ rep Asif

This question........especially the third one was haunting my mind as well ;)

Thanks for +rep :)
i was also stuck with the third one but after thinking for a while i found out how to do it ;D

Garfield:thank U ;D
missbeautiful789:U welcome :D
 
« Last Edit: October 11, 2010, 10:00:28 pm by asiftasfiq93 »
Logged


"A man's life is interesting primarily when he has failed - I well know. For it's a sign that he tried to surpass himself." Clemenceau, Georges

Offline rocker

  • Newbie
  • *
  • Posts: 9
  • Reputation: 292
Re: CIE AS P1 Math Problem M/J 2010
« Reply #7 on: October 12, 2010, 08:08:40 am »
Another method
Consider the right angle triangle with x angle.let triangle be ABC WITH AC hypotenuse.THE
Tan X =BC/AB
k=Bc/AB
Bc=kAB
how find Ac by using paythagrous therom which gives Ac^2=Bc^2+AB^2
and AC=bc(k^2+1)^(1/2)
now use sIN x=BC/Ac
put value of Ac and Bc=KAB it will give you
sin x=K/(K^2+1)^1/2
thank you
ITseems like complicated but try by drying triangle.
Logged

Offline Deadly_king

  • <<Th3 BO$$>>
  • Global Moderator
  • SF Farseer
  • *****
  • Posts: 3391
  • Reputation: 65078
  • Gender: Male
  • Hard work ALWAYS pays off.........just be patient!
    • @pump_upp - best crypto pumps on telegram !
Re: CIE AS P1 Math Problem M/J 2010
« Reply #8 on: October 13, 2010, 11:57:25 am »
Quote from: rocker on October 12, 2010, 08:08:40 am
Another method
Consider the right angle triangle with x angle.let triangle be ABC WITH AC hypotenuse.THE
Tan X =BC/AB
k=Bc/AB
Bc=kAB
how find Ac by using paythagrous therom which gives Ac^2=Bc^2+AB^2
and AC=bc(k^2+1)^(1/2)
now use sIN x=BC/Ac
put value of Ac and Bc=KAB it will give you
sin x=K/(K^2+1)^1/2
thank you
ITseems like complicated but try by drying triangle.

yeah.......I got it :)

It's indeed easier and simpler ;)

+rep to you as well
Logged
Pages: [1]   Go Up
« previous next »