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ALL CIE CHEMISTRY DOUBTS HERE !!

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iluvme:

--- Quote from: Ari Ben Canaan on May 27, 2011, 11:15:56 am ---WOAH ! That's a lot. I'll see if I can provide you with some hints.

--- End quote ---

:) Thanks.

elemis:
Question 10

A catalyst serves to LOWER the activation energy... does that help ?

Question 40

Alkaline Hydrolysis gives you the Sodium salt and the alcohol

Question 38

To determine if Option 1 is correct, look at the double bonds and the alcohol group at the end. KMnO4 would oxidise the alcohol to what ? An aldehyde or a ketone ? If you cant tell, then look at the no. of carbons the hydroxyl group is joined to.

Next, look at the double bonds. Can you see a place where a secondary alcohol (which upon further oxidation would form a ketone) could forrm as a result of oxidation by KMnO4 ?

Option 2 should be easy to prove/disprove.

Option 3 - Hint: Can you see any carboxylic acid groups ?

elemis:
Question 30

It is a liquid at room temperature and atmospheric pressure.

Ethane is a gas and the others are liquids.

It does not mix completely with water.

To mix with water you need to be able to form hydrogen bonds. This statement implies that the mystery compound DOES NOT form hydrogen bonds.

It does not decolourise acidified potassium manganate(VII).

The mystery compound will not undergo oxidation.

Question 29

There is no easy way to solve these kind of questions. Just draw out the structures and see if it helps.

iluvme:

--- Quote from: Ari Ben Canaan on May 27, 2011, 11:31:35 am ---Question 10

A catalyst serves to LOWER the activation energy... does that help ?

Question 40

Alkaline Hydrolysis gives you the Sodium salt and the alcohol

Question 38

To determine if Option 1 is correct, look at the double bonds and the alcohol group at the end. KMnO4 would oxidise the alcohol to what ? An aldehyde or a ketone ? If you cant tell, then look at the no. of carbons the hydroxyl group is joined to.

Next, look at the double bonds. Can you see a place where a secondary alcohol (which upon further oxidation would form a ketone) could forrm as a result of oxidation by KMnO4 ?

Option 2 should be easy to prove/disprove.

Option 3 - Hint: Can you see any carboxylic acid groups ?



--- End quote ---

Q 10, Energy is more at Ea1, which means activation energy is more? so uncatalysed reaction. Righto

Q 40, I was confused about the word partial. :/

Q 38, Right right right, Didn't notice that part, about COOH being absent.

iluvme:

--- Quote from: Ari Ben Canaan on May 27, 2011, 11:37:07 am ---Question 30

It is a liquid at room temperature and atmospheric pressure.

Ethane is a gas and the others are liquids.

It does not mix completely with water.

To mix with water you need to be able to form hydrogen bonds. This statement implies that the mystery compound DOES NOT form hydrogen bonds.

It does not decolourise acidified potassium manganate(VII).

The mystery compound will not undergo oxidation.

Question 29

There is no easy way to solve these kind of questions. Just draw out the structures and see if it helps.

--- End quote ---

Right, got both. :)
Though Q 29, I got mixed up with the (CH3)2C(OH) part.

Thanks Ari. :)

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