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ALL CIE CHEMISTRY DOUBTS HERE !!

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iluvme:
This question please,

When 1 mole of HI is allowed to dissociate, in a 1.0 dm-3 vessel at 4500C, only 0.78 mol of HI are present at equilibrium. What is the Kc value for this reaction?

Amii:
                          2HI (g)        ----------->       H2 (g) +     I2 (g)
                                           <-----------

Intial moles               1                                    0              0
Change                 (1-0.78)                          (0.5X0.22)    (0.5X0.22)
                             -0.22                             +0.11           +0.11
Moles at equilibrium   0.78                               0.11            0.11

Conc at equilibrium   (0.78/1 )                         (0.11/1)      (0.11/1)
mol dm-3                 0.78                                0.11            0.11

Kc = [H2][I2]
      ---------
        [HI]2

Kc= 0.11mol dm-3 X0.11 mol dm-3

      ---------------------------

        (0.78 mol dm-3 ) 2

=0.0199 no units

I hope it's right

iluvme:
Thank You! <3

Amii:

--- Quote from: i<3SL on March 20, 2011, 03:49:02 pm ---Thank You! <3



--- End quote ---
No problem  :D
Check it again.I modified it.

iluvme:

--- Quote from: Amii on March 20, 2011, 03:52:42 pm ---No problem  :D
Check it again.I modified it.



--- End quote ---

Thanks again.

Didn't notice anything wrong. Was just going through the steps. :)

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