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ALL CIE CHEMISTRY DOUBTS HERE !!

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Deadly_king:

--- Quote from: $!$RatJumper$!$ on November 18, 2010, 02:04:53 pm ---W04 Q3 pls
:)

--- End quote ---

It's just like Ari explained the previous number.

10CH2SH + 30O2 -----> 10CO2 + 10SO2 + 20H2O

When cooled, the water will condense. Hence it will no more be in gaseous state.

NOTE: 60cm3 of oxygen was available and only 30cm3 were used . So there are 30cm3 in excess.

In all it makes 50cm3

Therefore answer is C.

komailnaqvi:
Equation should be X + Cl2 => XCl2
Right so , X is supposed to be 2.920g
and the Xcl2 is 5.287
subtract the two to get the mass of Chloride used which will come out to be = 2.367g
Mass/Mr = 2.367/71 will get you moles of Chloride which are = 0.333333
Mole Ratio is 1:1
if 0.3333 mole of X is 2.920
then how much will be in one mole = 2.920/0.3333 = 87.9g
Thus Ans is C.
Strontium

cs:
An urgent one:

June 2010 P11, Q1 please...

Hypernova:

--- Quote from: komailnaqvi on November 18, 2010, 02:24:57 pm ---then how much will be in one mole = 2.920/0.3333 = 87.9g
Thus Ans is C.
Strontium

--- End quote ---

Nah, thats what i did. You get the MR=87.9, but the Mr of strontium is 38

komailnaqvi:
buddy Mr is 88 , atomic number is 38.

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