Qualification > Sciences
ALL CIE CHEMISTRY DOUBTS HERE !!
$!$RatJumper$!$:
Nov. 09 Varient 1 Q5,21,28,31 Thankx
Deadly_king:
--- Quote from: birchy33 on November 15, 2010, 11:30:56 pm ---Cheers mate, I'm just a bit unsure about the 2x + x = 1 bit. Secondly There's another equilibrium question: Question 9 from MJ/07. Your help would be much appreciated. Cheers + rep.
--- End quote ---
JUn 07 p1 No 9
Kc for reaction 1 is given to be equal to 2.
Kc = [X2Y]2 / [X2]2[Y2] = 2
For reaction 2 ---> Kc = [X2][Y2]1/2 / [X2Y]
If you square the Kc equation for reaction 2, you'll find that it becomes the reciprocal of the Kc equation for reaction 1. ;)
Hence for reaction 2 ---> Kc2 = 1/2.
So Kc will come to be (1/2)1/2 ----> Kc = 1/(21/2)
Answer is A.
Hope it's clear now :D
cs:
--- Quote from: Deadly_king on November 16, 2010, 11:53:39 am ---The 50% indicates that the equilibrium is at dynamic equilibrium. ;)
Since 50% of reactant becomes products while the other 50% remains as reactants. ;D
--- End quote ---
ok, got it finally, my third question please, anyone.. Thank you!
I have two days to do chem and i'm done. ;D
Deadly_king:
--- Quote from: cs on November 16, 2010, 12:06:18 pm ---ok, got it finally, my third question please, anyone.. Thank you!
I have two days to do chem and i'm done. ;D
--- End quote ---
No problem ;)
Same for me. Last exam on Friday though i'll be having Bio on Thursday. ;)
Jun 06 No 25
Radicals result from chlorofluorocarbon by the loss of a chlorine atom. ;)
This is because it is the most unstable and most weak bond within any CFCS. C-F is a very strong and stable bond which is not affected by U.V and so is C-H bond.
So you just need to look for an answer which lacks a chlorine atom.
Only C shows this. ;D
cs:
--- Quote from: Deadly_king on November 16, 2010, 12:11:51 pm ---No problem ;)
Same for me. Last exam on Friday though i'll be having Bio on Thursday. ;)
Jun 06 No 25
Radicals result from chlorofluorocarbon by the loss of a chlorine atom. ;)
This is because it is the most unstable and most weak bond within any CFCS. C-F is a very strong and stable bond which is not affected by U.V and so is C-H bond.
So you just need to look for an answer which lacks a chlorine atom.
Only C shows this. ;D
--- End quote ---
understood, i thought of that too, but not so sure.Thanks! My friends are sitting for Bio on Thursday too.. I'm not :P Good Luck!
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