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ALL CIE CHEMISTRY DOUBTS HERE !!
Deadly_king:
--- Quote from: Twinkle Charms on September 25, 2010, 05:50:27 pm ---Q) Tin reacts with iodine in an organic solvent to form a covalent compound SnIx when 0.4650g of Sn (in excess) was used; all the iodine reacted. A mass of 0.1230g of unreacted Sn and 1.8020g of SnIx were obtained. Find the value of x.
ok so i got the mass of Sn used by subtracting 0.1230 from 0.4650 =0.342g, now for iodine how do i go about? subtract the mass of Sn used from the total mass of the product that is 1.8020? or i find it thru the mole ratio thing? if tht is so then how do i know the number of moles of each and how can i write a balanced equation out of it when we have SnIx ??
--- End quote ---
Equation is as follows :
Sn + (x/2)I2 ----> SnIx
Forget about the number of moles of iodine to be used.
From equation whatever be the value of x,
1 mole of Sn will form 1 mole of SnIx
Number of moles of Sn used = Mass/Ar = 0.342/119
Therefore same number of moles of SnIx must be formed.
Number of moles of SnIx formed = Mass/Mr = 1.8020/(119+127x)
In other words :
1.8020/(119+127x) = 0.342/119
Solve this equation and obtain x = 4
Hope you understand :)
Feel free to ask if you have any doubt :)
Twinkle Charms:
--- Quote from: Deadly_king on September 25, 2010, 06:13:35 pm ---Equation is as follows :
Sn + (x/2)I2 ----> SnIx
Forget about the number of moles of iodine to be used.
From equation whatever be the value of x,
1 mole of Sn will form 1 mole of SnIx
Number of moles of Sn used = Mass/Ar = 0.342/119
Therefore same number of moles of SnIx must be formed.
Number of moles of SnIx formed = Mass/Mr = 1.8020/(119+127x)
In other words :
1.8020/(119+127x) = 0.342/119
Solve this equation and obtain x = 4
Hope you understand :)
Feel free to ask if you have any doubt :)
--- End quote ---
wow thanks =)
Deadly_king:
--- Quote from: Twinkle Charms on September 25, 2010, 07:03:15 pm ---wow thanks =)
--- End quote ---
Mention not :)
$!$RatJumper$!$:
Hey guys
Just a question in chem. For AS inorganic 9.1(e), in the syllabus it says:
"describe the reactions, if any, of the elements with oxygen and chlorine (to give Na2O etc)"
Does describe mean we just learn the equations or also the conditions under which these oxides and chlorides are made?
Deadly_king:
--- Quote from: $!$RatJumper$!$ on September 26, 2010, 11:35:56 am ---Hey guys
Just a question in chem. For AS inorganic 9.1(e), in the syllabus it says:
"describe the reactions, if any, of the elements with oxygen and chlorine (to give Na2O etc)"
Does describe mean we just learn the equations or also the conditions under which these oxides and chlorides are made?
--- End quote ---
You need to know their conditions as well. Sometimes you might be asked the colour of their flames when the metals are burnt.
NOTE : The conditions are not difficult to remember. Most of them are just heating.
But you need to know the reactions that the oxides or chlorides undergo. I mean you may be asked to describe their trends.
Here's a link which may be helpful :
http://www.chemguide.co.uk/inorganic/group1/reacto2.html#top
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