Qualification > Sciences
ALL CIE CHEMISTRY DOUBTS HERE !!
Deadly_king:
--- Quote from: moon on November 05, 2010, 11:45:16 pm ---can u help me in another Question plz.
June 08 Q2 a (ii) explain and draw the diagram. thank u very much for ur help.
--- End quote ---
::O=:Cl.=O::
Valence electrons = 19
Chlorine attaches to the oxygens through double bonds, and and each oxygen has two lone pairs to complete its octet. The chlorine also one lone pair and one electron. Chlorine in this structure obviously does not obey octet rule but in chlorine there is 3d subshell in which electrons are promoted and hence chlorine can also have 3,5 and 7 bonds.
Since chlorine has one lone pair, the ClO2 molecule will be a bent(v-shaped) one but not the same angle as H2O since it has only one lone pair.
For more details click here.
moon:
--- Quote from: Deadly_king on November 06, 2010, 06:28:44 am ---::O=:Cl.=O::
Valence electrons = 19
Chlorine in this structure obviously does not obey octet rule but in chlorine there is 3d subshell in which electrons are promoted and hence chlorine can also have 3,5 and 7 bonds.
--- End quote ---
How can we know the number of valence electrons?????and how can we know that chlorine is not obeying octet rule???
how do we determine the number of bonds formed by the chlorine in this case????
For the question above
how to construct a balanced ionic equation for its disproportionation.
Thanx in advance
$H00t!N& $t@r:
can someone please help me with this:
Q) A flask containing a mixture of 0.200 mol of ethanoic acid and 0.11 mol of ethanol was maintained at 25 degrees Celsius until the following equilibrium had been established.
CH3C00H + C2H5OH <-> CH3COOC2H5 + H2O
The ethanoic present at equilibrium required 72.5 cm3 of a 1.50 mol dm-3 solution of sodium hydroxide for a complete reaction.
- Calculate the value of the equilibrium constant Kc for this reaction at 25 degrees Celsius
- The enthalpy change for this reaction is quite small. By reference to the number and type of bonds broken and made, explain how this might have been predicted.
Thanks in advance :)
and sorry i dont have the answer to this question because i found it on a website :-\
Deadly_king:
--- Quote from: moon on November 06, 2010, 11:53:08 am ---How can we know the number of valence electrons?????and how can we know that chlorine is not obeying octet rule???
how do we determine the number of bonds formed by the chlorine in this case????
For the question above
how to construct a balanced ionic equation for its disproportionation.
Thanx in advance
--- End quote ---
Valence electrons is the total number of electrons from the outermost shells of the atoms forming the molecule.
Number of electrons in the outermost shell of O : 6
Number of electrons in the outermost shell of Cl : 7
Hence valence electrons : 2(6) + 7 = 19
Hmm............in this case ClO2 is a neutral molecule which means that oxygen has a stable electronic configuration. Otherwise there would have been a negative charge.
For oxygen to have a stable electronic configuration, it should form two covalent bonds or gain two electrons. Cl is a non-metal which does not give electrons. The only plausible solution is that it formed two bonds with each O atom.
Hence structure of ClO2 => ::O=:Cl.=O::
Moreover in the question itself, it is stated that the bonds between Cl and O is double bond. ;)
I need to go now. I'll complete the answer asap :)
moon:
Thank you very very much for ur help :)
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