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Math P2 Oct/Nov 2001 HELP !!!

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twilight:
Page 5, Question 12

(a)       cos x = 1/2
        cosine is positive in first and fourth quadrant
            x   =  cos-1 0.5    =   60o
     and  x   =           360 - 60            = 300o             =>     therefore   x = 60 or 300

(b)       cos x   is greater than 0 in these    0 < x < 90    and    270 < x < 360
             and it is less than 1/2  in this      60 < x < 300
  so combining both the required vales of x    are    270 < x < 300

sweetsh:

--- Quote from: Q80BOY on May 05, 2009, 06:19:33 pm ---IGCSE (CIE) Mathematics Paper 2 Oct/Nov 2001

(i've attached the question paper)

Page 3, Question 5 (Done)

Page 4, Question 9 (Done)

Page 5, Question 12

Page 8, Question 19, Part (d)

Page 9, Question 20, Part (a) and (b)

Page 10, Question 22, Part (a) and (b)

Page 11, Question 24, Part (c) < -- when i use the formula distance = speed * time i get 20 (ans in m/s is 40)

Total Number of Questions: 7

I really hope u can help me out here  :D

--- End quote ---


Did they answer everything? If no tell me so I can answer the rest

sanity_master:
Amber......u got 12 (b) wrong......the answer of cosX should be below 1/2

and 359 is 0.99984...
it is 270<x<300

and for 19 (d)......i guess they wont accept that answer as u didnt use part (b) and (c).......i would've solved it if i had time


By the way.....u better start canceling Qs or ppl will just keep answering the same questions :D

twilight:
sanity master .. look at my answer up there  .. i xplained y

Christy:

--- Quote from: sanity_master on May 05, 2009, 07:09:31 pm ---Amber......u got 12 (b) wrong......the answer of cosX should be below 1/2

and 359 is 0.99984...
it is 270<x<300

--- End quote ---

sorry my bad ... but the rest is correct right ??

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