Qualification > Sciences
CIE physics paper 2
Deadly_king:
--- Quote from: *Hope* on September 15, 2010, 09:19:13 pm ---Thank you..I am flattered :D :-[ :P I like that I encourage to help :D
--- End quote ---
Hehe........i hope that 1 day i may be as encouraging as you are to others :)
Greed444:
can someone help explain what is phase angle 60 degree as in the OCT/NOV 2002 Q5
it would be great if someone can show me how to do the Q5b(i) too :)
Deadly_king:
--- Quote from: Greed444 on September 24, 2010, 05:55:45 pm ---can someone help explain what is phase angle 60 degree as in the OCT/NOV 2002 Q5
it would be great if someone can show me how to do the Q5b(i) too :)
--- End quote ---
By a phase angle of 60 degrees.......it meant that the wave T2 would be moving 60 degrees faster.
In other words, when wave T1 is at maximum amplitude at time t=0, wave T2 will be at maximum amplitude at time t=0.5
But both waves will be having same frequency, wavelength and period.
60 degrees is the phase angle. To be able to do Q5b(i) you should convert the phase angle to the time difference sine the graph is one of X against time.
Phase angle = (delta T)/T * 360
From the graph it is noted that period T= 3s.
Hence delta T will be 0.5s.
You just need to draw a wave with same amplitude, same frequency and wavelength........but which is just 0.5s faster.
Hope you understood........if not let me know and i'll try to be clearer :)
S.M.A.T:
Keep it up DK :D :D
+rep
Greed444:
--- Quote from: Deadly_king on September 24, 2010, 06:01:25 pm ---By a phase angle of 60 degrees.......it meant that the wave T2 would be moving 60 degrees faster.
In other words, when wave T1 is at maximum amplitude at time t=0, wave T2 will be at maximum amplitude at time t=0.5
But both waves will be having same frequency, wavelength and period.
60 degrees is the phase angle. To be able to do Q5b(i) you should convert the phase angle to the time difference sine the graph is one of X against time.
Phase angle = (delta T)/T * 360
From the graph it is noted that period T= 3s.
Hence delta T will be 0.5s.
You just need to draw a wave with same amplitude, same frequency and wavelength........but which is just 0.5s faster.
Hope you understood........if not let me know and i'll try to be clearer :)
--- End quote ---
Thank you DK ^^ your explanations are crystal clear! :D
Navigation
[0] Message Index
[#] Next page
[*] Previous page
Go to full version