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statistic

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hanzseah:
how to do a lvl cie statistic may/june 2010 qp_63 ques 6? ???

Freaked12:
What part you dont understand.

S.M.A.T:
i)The number of insect in country X is 71(10+18+16+16+11)
So the median is (n+1)/2(since 71 is an odd number) term i.e. ((71+1)/2)=36th term,which is 0.825cm

lower quartile is (71/4)=18th term(0.814cm),upper quartile=71*(3/4)=54th term(0.833cm)

inter-quartile range=upper quartile-lower quartile=0.833-0.814=0.019

ii)lower quartile of country Y=(83/4)=21th term(0.82qcm),upper quartile=63th term(0.85rcm)

inter-quartile range=upper quartile-lower quartile
0.028=0.85r-0.82q
since in stem-and-leaf diagram r is between 2&3 so it must be 2 or 3 and since q is between 3&4 so it must be 3 or 4  .At the same time the difference between upper quartile & lower quartile must be 0.028cm,so when r=2 & q=4,all the above condition matches.

hanzseah:
hw bout the iqr?

S.M.A.T:
see above i modified my post ::)

i hope this helped :)

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