Qualification > Reference Material
IGCSE Math - Bearing
elemis:
Question 2
a) Looking at diagram 2 first add up the straight side lengths. 6 + 22 + 18 + 10 = 56
Then find the the arc length of the quarter circle in the top left hand corner. This is done by = 18.849 + 56 = 74.8 cm
b) Looking at diagram 2 again. 10 x 18+ 6 x 12 + 0.25 x pi x 122 = 365 cm2
c) Take the area previously calc. and multiply by the length (40 cm).
d) tomorrow. Have to go now.
Galleria:
loooool thanks !
do you know physics/chem ?
Can you answer this question generally?
If there are two electrodes connected to a voltmeter and a circuit, then how do we ensure that the gap between them remains equal or how can we measure the gap without putting a ruler inside the beaker ? . lol
Arthur Bon Zavi:
--- Quote from: Galleria on September 06, 2010, 01:33:17 pm ---loooool thanks !
do you know physics/chem ?
Can you answer this question generally?
If there are two electrodes connected to a voltmeter and a circuit, then how do we ensure that the gap between them remains equal or how can we measure the gap without putting a ruler inside the beaker ? . lol
--- End quote ---
By Using Sensors connected to the computer!
elemis:
--- Quote from: Galleria on September 06, 2010, 01:33:17 pm ---loooool thanks !
do you know physics/chem ?
Can you answer this question generally?
If there are two electrodes connected to a voltmeter and a circuit, then how do we ensure that the gap between them remains equal or how can we measure the gap without putting a ruler inside the beaker ? . lol
--- End quote ---
I did Physics and Chem for my IGCSEs ;)
I remember this question - from paper 6, right ?
I wrote separate the electrodes using a block of wood. My teacher said that would be an acceptable answer.
Arthur Bon Zavi:
Q was - The student wishes to measure the height of the image on the screen in order to check
his result. However he finds that when he tries to do this his hand and the rule prevent
the light reaching the screen. Suggest briefly a method he could use to measure the
height of the image on the screen that would overcome this problem.
AND This Was the Answer as on the marksheet:
scale drawn on paper on screen/graph paper on screen/
mark on screen (then) measure/clamp ruler on scale/
use translucent screen and measure from other side :o
;D ;D ;D
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