Qualification > Sciences

Collisions in two dimensions problem (urgent)

(1/3) > >>

xim7007:
A shell of mass 12kg moving horizontally at 320m/s explodes into three fragments A, B and C,
which continue to move in a common vertical plane.

Fragment A: mass= 2kg, speed= 450m/s, 45degree above the horizontal
Fragment B: mass=6kg, speed=400m/s, moves horizontally
Fragment C: mass=m, speed=v, in a direction teta to the horizontal

Calculate the size of the momentums of the shell before it explodes and of fragments A and B
afterwards.  :) help me...

Deadly_king:
well momentum is the product of mass and linear velocity.

so for the shell.......momentum = 12*320 = 3840 Ns

You need to find the component of velocity along the horizontal plane since momentum requires value for linear velocity. So fragment A : p = 2*(450cos45) = 636.4 Ns

Fragment B : p = 6*400 = 2400

If you the apply the law of conservation of momentum you can find the momentum of fragment C too.

p = 3840 - (2400+636.4) = 803.6 Ns

Hope i've been able to help you. If u dont understand do ask.......i'll try to make myself clearer

Alpha:
Thank you for helping Deadly_King. +rep. :)

Deadly_king:
hehe.........its alright!!

i told you......i love to help others........i just hope that i've made myself clear enough!

Alpha:
Sure enough. :)

Navigation

[0] Message Index

[#] Next page