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IGCSE MATHS DOUBTS HERE !!!!

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**RoRo**:
Paper 2, June 2001.

The capacity of a jug is 3.5 litres correct to the nearest 0.1 litre.
The capacity of a glass is 0.25 litres correct to the nearest 0.01 litre.

b) Calculate the greatest number of glasses which you can be sure to fill from a full jug.

Can someone please explain to me how do you arrive to this answer? Thanks!

elemis:
One moment.

elemis:

--- Quote from: The Secret on December 11, 2010, 12:00:50 pm ---Paper 2, June 2001.

The capacity of a jug is 3.5 litres correct to the nearest 0.1 litre.
The capacity of a glass is 0.25 litres correct to the nearest 0.01 litre.

b) Calculate the greatest number of glasses which you can be sure to fill from a full jug.

Can someone please explain to me how do you arrive to this answer? Thanks!

--- End quote ---

We need to find the largest possible capacity of the jug and the SMALLEST possible capacity of the glass.

LARGEST capacity of jug = 3.55

SMALLEST capacity of glass = 0.255

Hence, 3.55/0.255 = 13 glasses (dont round up)

SauD~:
I want some help, in indices and graph of functions. I only need the method of solving the indices without calculator and in the graphs i want to know how to find solution. here are some eg.
Indices:-   9^1/2 x 3^5/2                        
               --------------                                                       
               3^2/3 x 3^-1/6                                             
                   
 Graphs of function:- a) Plot a graph of function equation y=2x^2-5x-5 for -2 =<x=<5.
b) Use the graph to solve the 2x^2-5x-5=0.                      
c) Show you method clearly, use the graph to solve the equation 2x^2-3x=10.

part c) with the method is necessary :)

if you need the answer then the answer for indices is 27 and the answer for graph thing of part c) is x= -1.6 and 3.1

x --> multiplication sign   &   x --> X, the unknown value..
Thanks, :)

Amii:

--- Quote ---Indices:-   9^1/2 x 3^5/2                        
               --------------                                                      
               3^2/3 x 3^-1/6
--- End quote ---


9^1/2 x 3^5/2

9^1/2 = Square root of 9 = 3 which is same as 3^1

so 3^1 X 3^5/2

1/1 + 5/2 = 3.5

1x2  +  5x1  = 2 + 5 = 7   = 3.5
----    ----    -----    --
1x2      2x1       2       2

3^3.5 or 3^7/2

3^2/3 x 3^-1/6

2/3 -1/6 = 3/6

2x2 - 1x1   = 4-1 = 3   
----  ----     ----   --
3x2    6x1      6      6

so 3^3/6

(3^7/2 ) / (3^3/6)

(7/2) - (3/6) = 3

7x3 - 3x1 =  21-3  = 18    = 3
---    ---     -----    ---
2x3   6x1       6        6

so 3^3 = 27

Okay saud?  :D

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